Question

a constant force acting on a body of mass M1 produces an acceleration of 4.00 m/s^2 the same force applied to the another body of mass M2 produces an acceleration of 2.00 m/s^2 if M1 and M2 are combined what is the common acceleration under the action of the same force​

Answer 1

Answer:

4/3

Explanation:

F=M1(4)----eq(1)

F=M2(2)-----eq(2)

solve EQ (1) &(2)

We get

M2=2M1

so,

(M1+M2)=3M1

now,

same force is applied so,

F=3M1(a)

from EQ (1)

4M1=3M1(a)

a=4/3