Question

A constant force acts for 10 s, on a stationary body of mass 10 kg after which the force ceases to act.
The body moves a distance of 50 m in next 5 s. The magnitude of force is
[ ]
b) 0.4 N
c) 40 N
d) 400 N
a) 4 N
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Answer 1

Answer:

The Force exerted upon the body is equal to 10N.

Explanation:

Mass (m) = 10 kg

Distance (S) = 50 m

Time (t) = 10 seconds

Initial Velocity (u) = 0 m/s

Final Velocity (v) = Let it be v.

According to the formula,

= v = S/t

= 50/5 m/s

= 10 m/s

Acceleration (a) = (v-u)/t

= v/t

= 10/10 m/s²

= 1 m/s²

Force = ma

= [10*1] N

= 10 N

Hope this helps.