A constant force acts on a particle and its displacementy
(in cm) is related to t (in s) by the equation t= Vy-2+3.
What is the displacement of the particle when its velocity
is zero?
(1) 4.5 cm
(3) 2 cm
(
2
(2) 3 cm
(4) 5.5 cm
Answers
Answer:
Answer:
Given:
Considering the Time Vs Displacement relationship to be as follows :
t = \sqrt{(x + 3)}t=
(x+3)
To calculate:
Displacement of particle when Velocity is zero.
Concept:
We will try to differentiate the given function and get the Displacement vs To function :
t = \sqrt{(x + 3)}t=
(x+3)
= > x + 3 = {t}^{2}=>x+3=t
2
= > \dfrac{d(x + 3)}{dt} = \dfrac{d {t}^{2} }{dt}=>
dt
d(x+3)
=
dt
dt
2
= > \dfrac{dx}{dt} + 0 = 2t=>
dt
dx
+0=2t
= > v = 2t=>v=2t
Now , let's find the time for which velocity is zero.
Putting v = 0 , we get t = 0 ;
Now putting t = 0 in the 1st equation , we get :
t = \sqrt{(x + 3)}t=
(x+3)
= > 0 = \sqrt{(x + 3)}=>0=
(x+3)
= > x + 3 = 0=>x+3=0
= > x = - 3 \: cm=>x=−3cm
So final answer :
\boxed{ \large{ \blue{ \bold{ displacement = - 3 \: cm}}}}
displacement=−3cm