Question

A constant force acts on an object 10 kg for a duration of 5 seconds it increases the object velocity fro3m/s to 7m/s find magnitude of applied force

Answer 1

mass:-10kg
time:-5sec
u:-3m/sec
v:-7m/sec

a=v-u÷t
=7-3÷5
=4÷5
=.8m/s×s

F=ma
=10kg×.8
=8N