Question

A constant force acts on an object of 5 kg for a period of 2s .It increases
The velocity of an object from 3 m/s to 7 m/s. Find the magnitude of the
Applied force .now if the force was applied for a period of 5 s,what would
be the final velocity of the object?

Answer 1

v = u + at ... 13 m/s2

Answer 2

given datas : mass m = 5 Kg
time t = 2 s
initial velocity u = 3 m/s
final velocity v = 7 m/s
F = ?
Using F = ma
F =
$f = ma$
F = 5 N