Question

A constant force acts on an object of mass 5 kg for a duration of 2 second. It increases the objects velocity from 3 m/s to 7 m/s. FIND ITS MASS. Now if the force were applied for a duration of 5 second, what would be the final velocity of the object ?

Answer 1

Answer:

Explanation:

Hey dude

Let the Force be F 

mass = 5 kg 

time(t) = 2 s

initial velocity(u) = 3 m/s

final velocity(v) = 7 m/s

 so let the acceleration be a 

so a = (v - u)/t = (7 - 3)/2 = 2 m/s²

So the magnitude of the applied force is 10 N

and the final velocity after 5 s is v 

so v = u + at 

v = 3 + 2 x 5

v = 13 m/s 

The final velocity after 5 s is 13 m/s

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Answer 2

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