A constant force acts on an object of mass 5 kg for a duration of 2 seconds. It increases the object's velocity from 3 m/s to 7 m/s. What is the magnitude of the applied force?
a. 5 N
b. 15 N
c. 10 N
d. 20 N
Answers
Answered by
2
Answer:
c. 10N
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Answered by
1
m=5kg
a=7-3/2=2m/s2
F=ma
=5x2
=10N
a=7-3/2=2m/s2
F=ma
=5x2
=10N
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