A Constant force acts on an object of mass 5kg for a duration og 2s. It increases the objects velocity from 3m/s to 7m/s .Find th magnitude of applied force. Now, if the force was applied for a duration of 5s, what would be the final velocity of the object ????
Answers
Answered by
1
Answer:
applied force is 10N, final velocity of object is 13 m/s
Explanation:
F=m(v-u)/t
F=5(7-3)/2
F=10N
Answered by
0
Answer:
my free fire id is..... rocky2724A
and what's ur id
Similar questions