A constant force acts on an object of mass 5kg for a duration of 2 seconds. it increases the object's velocity from 3m/s to 7m/s.find the magnitude of applied force?
Answers
Answered by
11
Hey,
Mass = 5kg
Time = 2s
Initial velocity = 3m/s
Final velocity = 7m/s
Force = Mass×Acceleration
[ Acceleration = Final velocity - Initial velocity/Time]
Force = 5 × ( 7 - 3 / 2)
Force = 5 × (2)
Force = 10 N
Mass = 5kg
Time = 2s
Initial velocity = 3m/s
Final velocity = 7m/s
Force = Mass×Acceleration
[ Acceleration = Final velocity - Initial velocity/Time]
Force = 5 × ( 7 - 3 / 2)
Force = 5 × (2)
Force = 10 N
Similar questions