Question

A constant force acts on an object of mass 5kg for a duration of 2s.it increases the velocity of object from 4ms-1 to 8ms-1 find the magnitude of the applied force.

Answer 1

Given:

 Mass of the object = 5 kg

 u= 4 m/s

 v= 8 m/s

  t = 2 s

We know:

      F = ma

∵ a = v-u/t

By substituting values,

 a = 8 - 4 / 2 = 2 m /s^2

∵ F = ma

∴ F = 5 * 2

⇒ F =  10 N

Here's your answer friend.........

Answer 2

Hope this is helpful to U