Question

A constant force acts on an object of mass 6 kg for duration of 3 second it increases the object velocity from 3m/ s to 9m/s find the magnitude of the applied force

Answer 1

Answer:

12 N

Explanation:

acceleration = change in velocity / time = (9 - 3) / 3 = 2 m/s2

F applied = mass * acceleration

                =  6 * 2

                = 12 N

Answer 2

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