Question

A constant force is applied for 2s on a body of mass 5kg.
as a result, if the velocity of the body is changed from 3m/s to 7 m/s.
find the value of the force applied​

Answer 1

Answer:

10kg-m/s^(2)

Explanation:

v=u+at

7=3+a*2

a=2m/s^(2)

F=ma

=5*2

F=10

Answer 2

Answer:

ANSWER

m=5 kg, u=3m/s, v=7m/s, t=2s

a= v - u / t

7m/s−3m/s / 2s

=2m/s^2

Force F=ma = 5kg×2 m/s^2

=10 kg m/s^2

=10 N ( 10 newton)