A constant force of 12 N acts on a body for 4 s. Find the change in the linear momentum of the body.
Answers
Answered by
328
F=m(v-u)/t
So,
12=m(v-u)/4
Hence,
m(v-u)=12*4=48kgm/s
So, mv-mu=48kgm/s
Therefore change in linear momentum of the body is 48kgm/s.
So,
12=m(v-u)/4
Hence,
m(v-u)=12*4=48kgm/s
So, mv-mu=48kgm/s
Therefore change in linear momentum of the body is 48kgm/s.
Answered by
0
Answer:
48kgms^-1
Explanation:
Here,F=12N,
t=4s
F=mv-mu/t
Ft=mv-mu
12*4=48kgms^-1
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