Question

a constant force of 12 N acts on a body for 4 s.the change in the linear momentum of the body is

Answer 1

acceleration = F/m
= 12/m
change in velocity = 0 + 12/m × 4
( by v= u + at)
= 48/m

now change in momentum = m × (48/m) - 0 (final momentum - initial momentum)
= 48 Nm.

Answer 2

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Formula to be used:-
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$= > \bf \:linear \: \: momentum = mass \times velocity \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf = {force} \times {time}$
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=> FORCE (F) = 12N

=> Time (T) = 4 sec.

=> linear momentum
$= {f} \times {t} = 12 \times 4 = 48 \: \: kg \: m \: {s}^{ - 1}$

Change in momentum = 48-0 = 48


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