Question

A constant force of 5 Newton is applied continually on a object of mass 10 kh for 4 seconds the object moves 800 cm along a straight line what is the velocity of an object when the force was applied initially

Answer 1

First find acceleration :

F=ma --> a = F/m ---> a=5/10 = 0.5 m/s square

Now use the equation S=ut + 1/2 a t^2

800cm=8m ; Let initial velocity be u

8=u4 + 1/2 x 1/2 x (4x4)

8=4u + 4

4=4u --> u = 1 m/s

Answer 2

GIVEN

• Force = 5 N
• Mass = 10 kg
• Time = 4 sec
• Displacement = 800 cm or 8 m

TO FIND

• Initial Velocity

FORMULA USED

F = ma

S = ut + at²/2

CALCULATION

Acceleration = Force/Mass

• ⟹ a = 5/10
• ⟹ a = 0.5 m/s²

S = ut + at²/2

• 8 = 4u + 4*4²/2
• 8 = 4u + 32
• 4u = 24
• u = 4 m/sec