Question

. A constant force of 8N acting on an object displaces it through a distance of 3.0 m in the direction of force. Calculate work-done by the force on the object.​

Answer 1

Given :-

• $\sf Constant \: force(F) = 8 \: N$
• $\sf Displacement(s) = 3 \: m$

To Find :-

• $\sf Work \: Done(W.D) = ?$

Solution :-

We know that :-

${\red{\boxed{\small{\bold{Work\: Done\: =\: Fs\: Cos\theta}}}}}$

Here,

• $\sf\: \theta \: = 0 \degree$
• $\sf\: cos \: 0 \degree = 1$

Putting the given values :-

$\sf: \implies Work \: Done = FS \: cos \: \theta$

$\sf: \implies Work \: Done = 8 \times 3 \times cos \:0 \degree$

$\sf: \implies Work \: Done =24 \times 1$

$:\implies{\underline{\boxed{\frak{\red{Work \: Done = 24\;J}}}}}\;\bigstar$

• Hence, Work down 24 joule

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Answer 2

Work Done = Force multiplied by displacement
= 8(3)= 24J