Question

a constant retarding force of 10 Newton is excred to a body of mass 20 kg moving initially with a speed of 10 metre per second. how long does the body take to stop?





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Answer 1

Explanation:

Using , F = ma

As force is retarding it will be -F

-10 = 20a

a= -0.5

Using , a = (v-u)/t

As the body stops at the end , v = 0

Therefore , -0.5 = 0-10/t

-0.5 = -10/t

t = 20 seconds