Question

A constant retarding force of 100 newton is applied to a body of 10 kg moving initially with a speed of 30 m/s what is the retardation

Answer 1

as F=ma

and F=100N

m=10kg

putting values we get

a= -10ms-2

as force is opposing the motion

thus negative sign is used

magnitude of retardation is 10ms-2

Answer 2

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Retarding force,

F = –100 N

Mass of the body,

m = 10 kg

Initial velocity of the body,

u = 30m/s

Final velocity of the body,

v = 0

Using Newton’s second law of motion, the acceleration (a) produced in the body can be calculated as:

F = ma

=> –100 = 10 × a

=> a= -100/10 = -10 m/s^2

Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as:

v = u + at

=> t= -u/a = -30/-10= 3 sec.

I hope, this will help you

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