Question

A constant retarding force of 50n is applied to a body of mass 20 kg moving with a speed of 15m/s how long does the body move

Answer 1

50=20×a
a=50/20=2.5ms^-1
u=15m/s v=0 t=? a=-2.5
v =u+at
0=15-2.5t
time= 15/2.5=6secs

Answer 2

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$\bold\red{hello...frd\:swigy\:here}$

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Retarding force,

F = –50 N

Mass of the body,

m = 20 kg

Initial velocity of the body,

u = 15 m/s

Final velocity of the body,

v = 0

Using Newton’s second law of motion, the acceleration (a) produced in the body can be calculated as:

F = ma

=> –50 = 20 × a

=> a= -50/20 = -2.5 m/s^2

Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as:

v = u + at

=> t= -u/a = -15/-2.5= 6 sec.

I hope, this will help you

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