Question

A constant torque of 1500 N-m turns a wheel of M.I 300 kg m^2 about an axis passipassing through its center the angular velocity of the wheel after 3 second will be

Answer 1

Answer:15 rad/sec

Explanation:

Torque = Moment of inertia✖️ angular acceleration

Angular acceleration = 1500/300 = 5 rad/sec^2

Omega F. = omega I.+Angular acceleration✖️ time

Omega F. = 0 + 5✖️3

=15 rad/sec