Using divisibility test determine that no. 990 is devesible by 2 3 and 5
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The last digit of the number is an even number. Therefore, it is divisible by 2.
990=9+9+0=18
18 is a multiple of 3. Therefore, it is divisible by 3.
The number ends with 0. Therefore, it is divisible by 5.(A number which ends with 0 or 5 is divisible by 5)
Hope it helps....
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