Question

A constant-volume thermometer registers a pressure of 1.500 × 104 Pa at the triple point of water and a pressure of 2.050 × 104 Pa at the normal boiling point. What is the temperature at the normal boiling point?

Answer 1

The temperature at the normal boiling point is 373.31 K .

Explanation:

Step 1:

Given,  

Pressure at normal boiling point $\mathrm{P}=2.05 \times 10^{4} \mathrm{Pa}$

Let the triple point pressure of water is represented as Pt

Pressure at triple point of water $\mathrm{P}_{\mathrm{t}}=1.500 \times 10^{4} \mathrm{Pa}$

Temperature at triple point of water =$273.16 \mathrm{K}$

Step 2:

By using the formula,

$\mathrm{T}=\frac{P}{P_{t}} \times 273.16$

(This is relation in pressure and temperature)

$\mathrm{T}=\frac{\text { Pressure at given temperature }}{\text { pressure at triple point }} \times 273.16$

$=\frac{2.05 \times 10^{4}}{1.500 \times 10^{4}} \times 273.16$

Step 3:

By calculating above values we get    

$\mathrm{T}=373.31 \mathrm{K}$

Answer 2

${\bold{\huge{\red{\underline{\green{ANSWER}}}}}}$

373.31 K

hope it help