Question

a.
Construct A ABC, where AC = 3.5 cm, BC = 4cm and ZABC = 45°.​

Answer 1

*Answer:

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See the attachment given above

*Steps of construction:

1. Draw base BC of length 8 cm.
2. Now let's draw Angle B = 45°
3. Let the ray be BX.
4. Open the compass to length AB - AC = 3.5cm

Note: Since AB - AC = 3.5 cm is positive

So, BD will be above line BC .

5. From point B as the centre, cut an arc on Ray BX .

6. Let the arc intersect BX at D.

7. Join CD.

8. Now we will draw perpendicular bisector BD.

9. Mark point A where perpendicular bisector intersects B.

10. Join AC .

Hence ∆ ABC is a required triangle.

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