Question

A Container contains 192 liter of Milk. A seller draws out x% of Milk and replaced it with the same quantity of water. He repeated the same process for 3 times. And thus Milk content in the mixture is only 81 liter. Then how much percent he withdraw every time?

Answer 1

suppose 192 -3x =81

3x=192-81

x=192-81/3

x=37 answer

Answer 2

Answer:

19.2708%

Step-by-step explanation:

Given : A Container contains 192 liter of Milk. A seller draws out x% of Milk and replaced it with the same quantity of water. He repeated the same process for 3 times. And thus Milk content in the mixture is only 81 liter.

To Find: Then how much percent he withdraw every time?

Solution:

Since x % of milk is replaced every time .

So, amount of milk replaced each time = $x\% \times 192$

                                                                 = $\frac{x}{100}\times 192$

Since the process is repeated 3 times .

So, amount of milk is replaced = $\frac{3x}{100}\times 192$

Initially the amount of milk was 192 liters.

Amount of mil content in a mixture now = 81 liters.

A.T.Q

$192-\frac{3x}{100}\times 192=81$

$192-81=\frac{3x}{100}\times 192$

$111=\frac{3x}{100}\times 192$

$111 \times \frac{100}{192 \times 3}=x$

$19.2708333=x$

Thus the percent of withdraw every time is 19.2708%