A container contains 40 litre of a mixture of HCL and water in the ratio 3:1 .How much water should be added so that the ratio of HCL:Water becomes 1:3?
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30 :10 =40
30:10=40,3:1 =4 so to set 1 :3 ratio water should be 30 x3 is 90 so actual water content is 10 than 90 -10 = 80
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HCL in container
= 40/(3+1) X 3
= 10X 3 = 30 litre
Therefore Water = total - HCl = 40 - 30 = 10 litre
To make ratio 1: 3
HCL we have 30 litre , so we need water
30 X 3 = 90 litre
We already have 10 litre of water .
So water to be added = 90- 10 =80 litre.
= 40/(3+1) X 3
= 10X 3 = 30 litre
Therefore Water = total - HCl = 40 - 30 = 10 litre
To make ratio 1: 3
HCL we have 30 litre , so we need water
30 X 3 = 90 litre
We already have 10 litre of water .
So water to be added = 90- 10 =80 litre.
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