Question

. A container contains 60 l milk and 40 l water. How much quantity of water should be added in the container so that if shopkeeper sell the mixture of container at cost price of milk then he will earn 150% profit?
1 point
(a) 80 L
(b)100 L
(c) 30 L
(d) 50 L​

Answer 1

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Answer 2

The quantity of water to be added so that a profit of 150% is earned is 50L

Given:

Quantity of milk = 60L

Quantity of water = 40L

To Find:

Quantity of water to be added so that a profit of 150% is earned

Solution:

Let the water added to the container be = x

Since there are two different variants in the container and profit of 150% is needed.

Therefore,

According to the question -

60 / 40 + x = 2/3

3 ( 60) = 2 ( 40 + x)

180 = 80 + 2x

180 - 80 = 2x

100 = 2x

x = 100/2

x = 50

Answer: The quantity of water to be added so that a profit of 150% is earned is 50L

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