Question

a container having adiabatic walls is divided into 2 equal half by thermally conducting separator. temperature of chamber 1 and 2 are 25 C and 322 C respectively. The final temperature is T Kelvin. find value of (T/10)

Answer 1

322-25 = 297

297/2 = 148.5

the final temperature will be 173.5

apply the Kelvin formula

Answer 2

The final temperature (T) of the container can be determined by using the concept of thermodynamics, specifically the conservation of energy principle.

Since the container has adiabatic walls, no heat will be transferred in or out of the container. Therefore, the heat that is present in chamber 1 will be equal to the heat that is present in chamber 2.

To calculate T, we can use the equation:

(25 + T) = (322 + T) / 2

Solving for T, we get:

T = (322 - 25) / 2 = 148.5

Therefore, (T/10) = (148.5/10) = 14.85

To summarize:

• The container has adiabatic walls, meaning no heat is transferred in or out.
• The container is divided into two equal parts by a thermally conducting separator
• The temperature of chamber 1 is 25 C, and the temperature of chamber 2 is 322 C
• Using the conservation of energy principle, we can calculate the final temperature (T) to be 148.5 C
• (T/10) = 14.85

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