A container holds 50.0 mL of nitrogen at 298 K. What will be its volume if the temperature increases to 550 K at the same pressure.
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Given,
Volume 1 (V₁) = 50 mL
Temperature 1 (T₁) = 298 K
Temperature 2 (T₂) = 550 K
By Charles's law,
V₁/T₁ = V₂/T₂
= 50/298 = V₂/550
= 50*550/298 = V₂
= 9.22 mL = V₂
I hope this helps.
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