Question

A ladder 17.5 m long stands upright against a wall. how far must the bottom of the ladder pulled out,so that the height of top may be 14 m

Answer 1

Let the ladder touching the walls forms ABC

Length of the ladder = 17.5 m

Height of the wall where the ladder touches is

14m

AB = Ladder = 17.5 m

AC = Wall = 14 m

BC = Ground

Then, By Pythagorus theorem

BC² = AB² - AC²

= (17.5)² - 14²

= 306.25 - 196

= 110.25

BC = √110.25

= 10.5 m

I hope this will help u. Please add this to the brainlist.