Math, asked by asiraj227, 10 months ago

a container is filled with liquid 6 part of which are water and milk how much of the mixture must be​

Answers

Answered by BiswaShresikha
2

Answer:

yr answer is 1/5

Step-by-step explanation:

let the container initally contains 16L of liqued

let a L of liquid compressing with water.

Quantity of water in new mixture=(6+6a/16+a)L

quantity of milk in new mixture=(10-10a/16)L

A/Q(according to the question)

6-6a/16+a=10-10a/16

96-6a+16a=160-10a

20a=64

a=64/20

a=16/5

Therefore part of mixture replace=1/6*16/5=1/5

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