a container is filled with liquid 6 part of which are water and milk how much of the mixture must be
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Answer:
yr answer is 1/5
Step-by-step explanation:
let the container initally contains 16L of liqued
let a L of liquid compressing with water.
Quantity of water in new mixture=(6+6a/16+a)L
quantity of milk in new mixture=(10-10a/16)L
A/Q(according to the question)
6-6a/16+a=10-10a/16
96-6a+16a=160-10a
20a=64
a=64/20
a=16/5
Therefore part of mixture replace=1/6*16/5=1/5
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