a container is filled with water (refractive indez=1.33)upto a height of 33.25 . aconcave mirror is placed 15 cm above the water level and the image of an objplaced at the bottom is formed 25 cm below the water level .the focal length of mirror is?
Answers
Tãjìrûl Çhãûdhãry answered this.....
Refractive index of water = μ = 1.33Heigh of the concave mirror from the water surface h = 15 cmDepth of the object inside the water d = 33.25 cmdepth of the image inside the water = i = 25 cmObject distance from the mirror is uu = h+dμ = -15+33.2551.33 = -40cmv = h+iμ = -15+251.33 =-33.8 cmFocal lengthf = uvu+v= -40×-33.8-40-33.8f = -18.32 cm
Normally, container is filled with water (refractive indez=1.33) upto a height of 33.25 and height of 33.25.
The Distance of object from mirror = Distance of object from mirror = 15+33.254×3= 39.93 cm.
Distance of image from mirror =15 + 254×3=33.75 For mirror, 1v+1u=1f Þ 1−33.75−139.93=1fÞ f » ?18.3 cm.
Therefore, the correct answer will be 18.3 cm which is considered as the distance from the varied spots to the maximum.