Question

A container of 22.4 l volume contains a diatomic gas at ntp. How many atom(s) is/are present in the container?

Answer 1

Answer:

12.044 * 10^23

Explanation:

at NTP, volume = 22.4l

no. of moles = 1

no. of molecules in 1 mole = avogadro's no. * 1

= 6.022 * 10^23

no. of atoms in one molecule = 2

total no. of atoms = 2 * 6.022 * 10^23

= 12.044 * 10^23

Answer 2

Answer:

Explanation:

there are 12.046 x 10^23 atoms.

in one mole, 6.023 x 10^23 molecules

since the gas is diatiomic, there ar 2 atoms.....

Therefore, 2 x 6.023 x 10^23 atoms,

=> 12.046 x 10^23 atoms => 1.2046 x 10^24 atoms