Question

A disc of mass 5 kg and radius 20 cm is rolling with an angular speed 10 rad/s on the horizontal plane. The magnitude of angular momentum of the disc about origin is

Answer 1

Answer:

1

Explanation:

moment of inertia ( I ) about centre = MR²/2

= 5 * 20/100 * 20/100 * 1/2 = 1/10

angular momentum = I * angular speed

= 10 * 1/10 = 1

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Answer 2

Answer:

Mass(M)=5kg

Radius (R)=20cm=20×10^(-2)m=0.2 m

Angular velocity (q)=10 rad/s

Since disc is rotating in horizontal plane,

Moment of inertia of disc about origin(I)=MR^2/4

Angular momentum=Iq=M×R^2×q/4=5×0.2×0.2×10/4

Angular momentum = 1/2=0.5 kgm^2rad/s

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