A container of production line solvent is mixed at 22% strength and another is mixed at 53% strength.To obtain 12 liters of a mixture that is 25% strength, how many liters should be used from the container that is mixed at 53% strength?
Answers
Answered by
2
Answer:
Explanation:
Let the volume of solution with strength 22% is xL , then the volume of solution with strength 53% is (12-x) L as the total volume is made to be 12 L.
solving for x, x = 10.84 L
Thus the solution with strength 53% is (12-x) L=(12-10.84) L= 1.16 L
Similar questions