Question

a container of production line solvent is mixed at 22% strength and another is mixed at 53% strength.to obtain 12 liters of a mixture that is 25% strength how many liters should be used from the container that is mixed at 53% strength?

Answer 1

26 litre should be used

Answer 2

Answer: 1.16 Liters

Explanation:

Let the volume of solution with strength 22% is xL , then the volume of solution with strength 53% is (12-x) L as the total volume is made to be 12 L.

$22\times x+53\times (12-x)=25\times 12$

solving for x, x = 10.84 L

Thus the solution with strength 53% is (12-x) L=(12-10.84) L= 1.16 L