A container open at the top, is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm respectively. Find the cost of milk which can completely fill the container at the rate of Rs.21 per litre.
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by formula for volume of frustrum,
capacity of container= pie/3*h (R^2+r^2+R*r)
= 22/7/3*24 (20^2+8^2+20*8)
=25.14 (400+64+160)
=10,281 cm^3
•°•The cost of the milk= volume/1000*21 rs.
=10281/1000*21
=215.901
=215
•°• The cost of the milk contatiner can hold is ₹215.
I hope this'll help you.
capacity of container= pie/3*h (R^2+r^2+R*r)
= 22/7/3*24 (20^2+8^2+20*8)
=25.14 (400+64+160)
=10,281 cm^3
•°•The cost of the milk= volume/1000*21 rs.
=10281/1000*21
=215.901
=215
•°• The cost of the milk contatiner can hold is ₹215.
I hope this'll help you.
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