A container open at the top is in the form of a frustum of a cone of height 21 cm
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Solution :-
Radius of the upper end of the container = 20 cm
Radius of the lower end of the container = 8 cm
Container is in the shape of frustum.
Height of the frustum = 21 cm
Volume of the container = 1/3πh[R² + r²+ (R*r)]
⇒ 1/3*22/7*21*[20² + 8² + (20*8)]
⇒ 1/3*22/7*21*(400 + 64 + 160)
⇒ (462*624)/21
⇒ 288288/21
= 13728 cu cm
As we know that 1 litre = 1000 cu cm
So, 13728 cu cm = 13728/1000
= 13.728 litre
Rate of milk = Rs. 35 per litre
Total cost = 13.728 × 35
= Rs. 480.48
Answer.
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Can u help me???
What is the TSA ,CSS,and vol of frustum??
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TSA of frustum=πl(R+r)+πR²+πr²
CSA of frustum=πl(R+r)
Volume of frustum=1/3πh(R²+r²+Rr)
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