Question

A container whose capacity is 80 litre contains milk and water in the ratio 3:2 how much quantity of mixture should be replaced with milk so that in the final mixture .ratio if milk to water each 27:13

Answer 1

If the ratio of milk and water is 3:2, amount of milk = 80×3/5 = 48 L and amount of water = 80-48 = 32 L
If the ratio of milk and water is 27:13, amount of milk = 80×27/40 = 54 L and amount of water = 80-54 = 26 L
If we remove x L of mixture, 0.6x L of milk and 0.4x L of water are eliminated. We replace this mixture by pure milk (x L). Hence, there is a net 0.4x L increase in the amount of milk and 0.4x L decrease in the amount of water.
Difference in the amount of milk = 54-48 = 6 L.
This difference in the amount of milk = 6 L = 0.4x → x = 6/0.4 = 15 L

This means that 15 L of mixture should be replaced by 15 L of milk so that the final ratio of milk to water is 27:13.