Question

A contains 6 black marbles, 9 blue marbles, 4 yellow marbles and 2 green marbles. A marble is randomly selected, replaced, and a second marble is randomly selected. Find the probability of selecting a black marble. then a yellow marble,

SOLUTION:​

Answer 1

There are 21 marbles in a bag. 

        6 black

        9 blue

        4 yellow

        2 green

The probability of selecting black is $\frac{6}{21}$

The probability of selecting yellow is $\frac{4}{21}$

The probability of selecting black then yellow is $\frac{8}{147}$

P(A∪B) = P(A) * P(B)

= $\frac{6}{21}*$ $\frac{4}{21}$

= $\frac{8}{147}$

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