Question

A contract on construction job specifies a penalty for delay of completion beyond a
certain date as follows: Rs. 200 for the first day, Rs. 250 for the second day, Rs. 300 for the third day, etc. The penalty for each succeeding day being Rs. 50 more than for the
preceding day. The contractor delayed the work by 30 days.

i) Calculate, how much money he could have saved had he finished the work on time?

ii)Which values (any two) he must possess to finish the work on time?

Answer 1

( According to question here given )

A contract on construction job specifies a penalty for delay of completion beyond a
certain date as follows:

1st day :- ₹ 200

2nd day :- ₹ 250

3rd day :- ₹ 300

for succeeding day :- ₹ 50

The contractor delayed the work by 30 days.


( SOLUTION ) :-

【1 ans】 :-

here , it makes an AP ( arithmetic progression)
200, 250, 300.

now, we can say that

a = 200, d = 50 and n=30

we can find the penalty by using the sum of 30 terms.

Now, by using the formula

S = n / 2 [ 2a + ( n - 1 ) d ]

= 30 /2 ( 2 × 200 + 29 × 50 )

= 15 ( 400 + 1450 )

= 15× 1850

= ₹ 27750

therefore , The contractor has to pay the penalty of Rs 27750 if the work is delayed by 30 days.


【 2 ans】 :-

The values that the contractor needs to complete the work are :-

1) Hard work

2) discipline and dedication.

Answer 2

Answer:

The above answer is correct no need bro

Step-by-step explanation:

Thanks