A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows : Rs.200 for the first day,Rs.250 for second day,Rs.300 for the third day,etc.,the penalty for each succeeding day being Rs.50 more than the preceding day.How much money the contractor has to pay as penalty,if he has delayed the work by 30 days?
Answers
Answered by
16
Answer:
Given
a=200
d=50
n=30
according to Sn=n/2[2a+(n-1)d]
30/2[2(200)+(30-1)50]
15[400+1500-50]
15[1450]
27750 Rs
Answered by
11
Answer:
Step-by-step explanation:
given
a=200
d=50
n=30
according to Sn=n/2[2a+(n-1)d]
30/2[2(200)+(30-1)50]
15[400+1500-50]
15[1450]
27750 Rs
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