Question

secX+1=(2+root3)tanX​

Answer 1

✨ Thanks for asking✨✨✨

here is your answer ⤵⤵⤵⤵⤵⤵

$answer \\ given : \\ \\ \: \: secx + 1 = (2 + \sqrt{3} )tanx \\ so \: secx = (2 + \sqrt{3} ) tanx- 1 \\ this \: is \: the \: value \: of \: secx \\ now \\ lhs \\ secx + 1 \\ = (2 + \sqrt{3} )tanx - 1 + 1 \\ = (2 + \sqrt{3} )tanx \\ rhs \\ (2 + \sqrt{3} )tanx \\ \: \: lhs = rhs \\ hence \: proved \\ secx + 1 = (2 + \sqrt{3} )tanx$

✨✨hope it helps ✨✨✨
hai rishi saha