Math, asked by Revanth114, 9 months ago

A contract on construction job specifies a penalty for delay of completion beyon
certain date as follows: *200 for the first day, 250 for the second day, 300 for the ti
day, etc., the penalty for each succeeding day being 50 more than for the preceding
How much money the contractor has to pay as penalty, if he has delayed the work b
ays?​

Answers

Answered by Anonymous
4

Deconstructing jobs Pacific billion complementation money the contractor has to pay 50 more than for the preceding 300 for the 204 1st 2504 2nd 304 the tell them.

So, the delayed answer is 58.

OK dear...

Answered by RAAZ34
0

Answer:

Step-by-step explanation:

t can be observed that these penalties are in an A.P. having first term as 200 and common difference as 50.

a=200,d=50

Sum upto n terms (S  

n

​  

)=  

2

n

​  

[2a+(n−1)d]

Penalty that has to be paid if he has delayed the work by 30 days  

=S  

30

​  

 

= S  

30

​  

=  

2

30

​  

[2(200)+(30−1)50]

=15[400+1450]

=15(1850)

=27750

Therefore, the contractor has to pay Rs 27750 as penalty.

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