Question

A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: ₹200 for the first day, ₹250 for the second day, ₹300 for the third day ,etc., the penalty for each succeeding day being ₹50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30 days?​

Answer 1

Answer:

It can be observed that these penalties are in an A.P. having first term as 200 and common difference as 50.

a=200,d=50

Sum upto n terms (S

n

)=

2

n

[2a+(n−1)d]

Penalty that has to be paid if he has delayed the work by 30 days

=S

30

= S

30

=

2

30

[2(200)+(30−1)50]

=15[400+1450]

=15(1850)

=27750

Therefore, the contractor has to pay Rs 27750 as penalty.

Step-by-step explanation:

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Answer 2

Answer:

wait I will solve and then edit this answer

Step-by-step explanation:

just 10 minutes