a4+1=(a2÷b2)(4b2_b4_1)then what is the value of a4+b4
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a4 + 1 = [a2/b2](4b2 - b4 - 1)
Put b = 1 in the above equation,
⇒ a4 + 1 = a2 × 2
⇒ a4 + 1 - 2a2 = 0
⇒ a = +1
∴ a4 + b4 = 2
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I don’t knowkzkakallaal
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