Math, asked by singhkYog7essanth, 1 year ago

A contract on construction job specifies a penalty for delay of completion beyod a certain date as follows: RS 200 for the first day, Rs 250 for the second day , RS 300 for the third day, etc., the penalty for each succeeding day being RS 50 more than for the preceding day. fow much money the contractor has to pay as penalty, if he has delayed the work by 30 days?

Answers

Answered by agarwalikshita
3
1650 is the ans.
just add 50 to the sum
Answered by muskan2807
2

Answer:

It can be observed that these penalties are in an A.P. having first term

as 200 and common difference as 50.

a = 200 and d = 50

Penalty that has to be paid if he has delayed the work by 30 days

= S30

u must be knowing the formula of sum.

= 15 [400 + 1450]

= 15 (1850)

= 27750

Therefore, the contractor has to pay Rs 27750 as penalty.

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