Math, asked by pranitagohain9, 10 months ago

A contractor employed 210 men to build a house in 60 days.After 12 days,he was joined by 70 more men.In how many days will the remaining work be finished?​

Answers

Answered by rosey25
4

Answer:

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Answered by Anonymous
3

Answer:

Total work = 210 x 60 = 12600 mandays.

Work finished in 12 days = 12600 x 12/60 = 2520 mandays

Remaining work = 12600 - 2520 = 10080 mandays

Number of men now = 210 + 70 = 280

Number of days required = 10080/280 = 36 days.

Smart Method

Work done initially = 12 days

Days remaining = 48 days.

Increase in manpower = 70 men = 1/3

If 1/3rd manpower increase, then 1/(1+3)th time will decrease.

=> Decrease in time= 48 x 1/4 = 12 days

=> Work will be completed in 36 days.

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