A contractor engaged 15 men to complete a job in 12 days. However, he soon found that three small boys can do the work of one man and have to be paid less. If he engaged 6 boys and 7 men to complete the job, find the time taken by them to complete the job?
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Answer:
20 days
Step-by-step explanation:
Find the equivalent of 6 boys in term of men:
3 boys = 1 man
1 boy = 1 ÷ 3 = 1/3 man
6 boys = 1/3 x 6 = 2 men
Find the manpower in term of men:
6 boys + 7 men = 2 + 7 = 9 men
Find the number of days needed:
15 men = 12 days
1 man = 12 x 15 = 180 days
9 men = 180 ÷ 8 = 20 days
Answer: 20 days
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