A contractor undertakes to make a road in 40 days and employs 25 men. after 24 days, he finds that only one third of the road is made. how many extra men should he employ so that he is able to complete the work 4 days earlier
Answers
Answered by
37
25 men in 24 days only completed 1/3 work
Work remaining = 2/3
Now some additional men is to be employed to complete the work 4 days earlier, that is, in 36 days(from start)
Days remaining = 36-24 = 12 days
M1*D1/W1 = M2*D2/W2 ... [M1,M2:Men; D1,D2:Days; W1,W2:Work]
Let the number of men to be added be 'x'
25*24/(1/3) = (25+x)*12/(2/3)
25*24 = (25+x)*12/2
100 = 25 + x
x= 75
Hence, 75 more men is to be employed to finish the work 4 days earlier.
Hope this helps
Work remaining = 2/3
Now some additional men is to be employed to complete the work 4 days earlier, that is, in 36 days(from start)
Days remaining = 36-24 = 12 days
M1*D1/W1 = M2*D2/W2 ... [M1,M2:Men; D1,D2:Days; W1,W2:Work]
Let the number of men to be added be 'x'
25*24/(1/3) = (25+x)*12/(2/3)
25*24 = (25+x)*12/2
100 = 25 + x
x= 75
Hence, 75 more men is to be employed to finish the work 4 days earlier.
Hope this helps
Answered by
0
Answer:
He should employ 75 extra men.
Step-by-step explanation:
Given is,
employs=25
Undertook road in= 40 days
1/3 wrk done= 24 days
we have to find out extra men
Solution:
Suppose the extra men = M
We will used following formula to find out how many extra men was working there.
M1N1/w1 = m2n2/w2
After puting value
25×24/(1/3) =( 25+)×12/(2/3)
=2/3×25×24=1/3(25+×12)
=400=100+
=300=
therefore
= 75
He should employ 75 extra men.
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