a vehicle of mass 20 kg is moving with a velocity of 4ms.find the madnitude of the force that is to be applied on the vehicle so that the vehicle has a velocity of 1ms after travelling a distance of 20 m.
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Answered by
3
v²-u²=2as
1²-4²=2*a*20
a=15/40
F=ma
20*15/40=7.5 N
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1²-4²=2*a*20
a=15/40
F=ma
20*15/40=7.5 N
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
pinkspink23:
but still u wont get 4 N
ans would be 7.5 N
actually dats the rght answer lekin in this book they have given the answer to be 4N
np i may be misprint
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
and my last ans too
plz
yea
thsnkd then
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Answered by
4
a = (v² - u²) / (2S)
= (1² - 4²) / (2 × 20)
= -0.375 m/s²
F = ma
= 20 kg × (-0.375 m/s²)
= -7.5 N
Here -ve sign indicates that Force should be applied in opposite direction to the motion of body
Magnitude of Force to be applied is 7.5 N
= (1² - 4²) / (2 × 20)
= -0.375 m/s²
F = ma
= 20 kg × (-0.375 m/s²)
= -7.5 N
Here -ve sign indicates that Force should be applied in opposite direction to the motion of body
Magnitude of Force to be applied is 7.5 N
thank u
You're welcome
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